php请求url链接地址并接收返回值 - 雅安论坛

方法1: 用file_get_contents 以get方式获取内容
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<?php
$url='http://www.domain.com/';
$html = file_get_contents($url);
echo $html;
?>
方法2: 用fopen打开url, 以get方式获取内容
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<?php
$fp = fopen($url, 'r');
//返回请求流信息（数组：请求状态，阻塞，返回值是否为空，返回值http头等）e799bee5baa6e79fa5e98193e59b9ee7ad9431333335343337
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stream_get_meta_data($fp);
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while(!feof($fp)) {
$result .= fgets($fp, 1024);
}
echo "url body: $result";
fclose($fp);
?>

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